Base | Representation |
---|---|
bin | 110001011111101001001… |
… | …000000001000110100101 |
3 | 110001011011120220120212102 |
4 | 301133221020001012211 |
5 | 421211204430333013 |
6 | 11122300441501445 |
7 | 500505441511655 |
oct | 61375110010645 |
9 | 13034146816772 |
10 | 3401230324133 |
11 | 10a14a9936884 |
12 | 46b2211a1885 |
13 | 1b897201c095 |
14 | ba898640365 |
15 | 5d719167d58 |
hex | 317e92011a5 |
3401230324133 has 32 divisors (see below), whose sum is σ = 3556427212800. Its totient is φ = 3250316716416.
The previous prime is 3401230324117. The next prime is 3401230324157. The reversal of 3401230324133 is 3314230321043.
It is a cyclic number.
It is not a de Polignac number, because 3401230324133 - 24 = 3401230324117 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3401230324096 and 3401230324105.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3401230324103) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 235420916 + ... + 235435362.
It is an arithmetic number, because the mean of its divisors is an integer number (111138350400).
Almost surely, 23401230324133 is an apocalyptic number.
It is an amenable number.
3401230324133 is a deficient number, since it is larger than the sum of its proper divisors (155196888667).
3401230324133 is a wasteful number, since it uses less digits than its factorization.
3401230324133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15161.
The product of its (nonzero) digits is 15552, while the sum is 29.
Adding to 3401230324133 its reverse (3314230321043), we get a palindrome (6715460645176).
The spelling of 3401230324133 in words is "three trillion, four hundred one billion, two hundred thirty million, three hundred twenty-four thousand, one hundred thirty-three".
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