Base | Representation |
---|---|
bin | 110001011111101001111… |
… | …101110100111111110001 |
3 | 110001011012120110020220211 |
4 | 301133221331310333301 |
5 | 421211222033232241 |
6 | 11122302104104121 |
7 | 500506002432613 |
oct | 61375175647761 |
9 | 13034176406824 |
10 | 3401244430321 |
11 | 10a15068a0a91 |
12 | 46b225a65041 |
13 | 1b8974c1a93a |
14 | ba89a472db3 |
15 | 5d71a502781 |
hex | 317e9f74ff1 |
3401244430321 has 2 divisors, whose sum is σ = 3401244430322. Its totient is φ = 3401244430320.
The previous prime is 3401244430279. The next prime is 3401244430343. The reversal of 3401244430321 is 1230344421043.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3341258623921 + 59985806400 = 1827911^2 + 244920^2 .
It is a cyclic number.
It is not a de Polignac number, because 3401244430321 - 211 = 3401244428273 is a prime.
It is not a weakly prime, because it can be changed into another prime (3401244430121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1700622215160 + 1700622215161.
It is an arithmetic number, because the mean of its divisors is an integer number (1700622215161).
Almost surely, 23401244430321 is an apocalyptic number.
It is an amenable number.
3401244430321 is a deficient number, since it is larger than the sum of its proper divisors (1).
3401244430321 is an equidigital number, since it uses as much as digits as its factorization.
3401244430321 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27648, while the sum is 31.
Adding to 3401244430321 its reverse (1230344421043), we get a palindrome (4631588851364).
The spelling of 3401244430321 in words is "three trillion, four hundred one billion, two hundred forty-four million, four hundred thirty thousand, three hundred twenty-one".
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