Base | Representation |
---|---|
bin | 11111101011010011… |
… | …111011100010011001 |
3 | 10020210101210012121111 |
4 | 133223103323202121 |
5 | 1024124214011213 |
6 | 23343012540321 |
7 | 2312602452631 |
oct | 375323734231 |
9 | 106711705544 |
10 | 34012641433 |
11 | 13474281a21 |
12 | 67129216a1 |
13 | 32907c1744 |
14 | 190932d6c1 |
15 | d41049a3d |
hex | 7eb4fb899 |
34012641433 has 2 divisors, whose sum is σ = 34012641434. Its totient is φ = 34012641432.
The previous prime is 34012641413. The next prime is 34012641469. The reversal of 34012641433 is 33414621043.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 28167580224 + 5845061209 = 167832^2 + 76453^2 .
It is a cyclic number.
It is not a de Polignac number, because 34012641433 - 217 = 34012510361 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 34012641395 and 34012641404.
It is not a weakly prime, because it can be changed into another prime (34012641413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17006320716 + 17006320717.
It is an arithmetic number, because the mean of its divisors is an integer number (17006320717).
Almost surely, 234012641433 is an apocalyptic number.
It is an amenable number.
34012641433 is a deficient number, since it is larger than the sum of its proper divisors (1).
34012641433 is an equidigital number, since it uses as much as digits as its factorization.
34012641433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20736, while the sum is 31.
The spelling of 34012641433 in words is "thirty-four billion, twelve million, six hundred forty-one thousand, four hundred thirty-three".
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