Base | Representation |
---|---|
bin | 1001111001100011010… |
… | …01000001010010010001 |
3 | 1012111221121111010200001 |
4 | 10330301221001102101 |
5 | 21033044111100022 |
6 | 420131142530001 |
7 | 33400603643221 |
oct | 4746151012221 |
9 | 1174847433601 |
10 | 340135253137 |
11 | 121283534a99 |
12 | 55b06736901 |
13 | 260c7c189c4 |
14 | 1266967a081 |
15 | 8caaeb0b27 |
hex | 4f31a41491 |
340135253137 has 2 divisors, whose sum is σ = 340135253138. Its totient is φ = 340135253136.
The previous prime is 340135253083. The next prime is 340135253149. The reversal of 340135253137 is 731352531043.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 252703268416 + 87431984721 = 502696^2 + 295689^2 .
It is a cyclic number.
It is not a de Polignac number, because 340135253137 - 211 = 340135251089 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 340135253096 and 340135253105.
It is not a weakly prime, because it can be changed into another prime (340135253537) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170067626568 + 170067626569.
It is an arithmetic number, because the mean of its divisors is an integer number (170067626569).
Almost surely, 2340135253137 is an apocalyptic number.
It is an amenable number.
340135253137 is a deficient number, since it is larger than the sum of its proper divisors (1).
340135253137 is an equidigital number, since it uses as much as digits as its factorization.
340135253137 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 113400, while the sum is 37.
The spelling of 340135253137 in words is "three hundred forty billion, one hundred thirty-five million, two hundred fifty-three thousand, one hundred thirty-seven".
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