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340147433 is a prime number
BaseRepresentation
bin10100010001100…
…011110011101001
3212201001021120002
4110101203303221
51144034204213
653430312345
711300130323
oct2421436351
9781037502
10340147433
1116500588a
1295ab86b5
1355616792
1433264613
151ecde658
hex14463ce9

340147433 has 2 divisors, whose sum is σ = 340147434. Its totient is φ = 340147432.

The previous prime is 340147421. The next prime is 340147447. The reversal of 340147433 is 334741043.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 175615504 + 164531929 = 13252^2 + 12827^2 .

It is a cyclic number.

It is not a de Polignac number, because 340147433 - 210 = 340146409 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 340147396 and 340147405.

It is not a weakly prime, because it can be changed into another prime (340147333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170073716 + 170073717.

It is an arithmetic number, because the mean of its divisors is an integer number (170073717).

Almost surely, 2340147433 is an apocalyptic number.

It is an amenable number.

340147433 is a deficient number, since it is larger than the sum of its proper divisors (1).

340147433 is an equidigital number, since it uses as much as digits as its factorization.

340147433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12096, while the sum is 29.

The square root of 340147433 is about 18443.0863198110. The cubic root of 340147433 is about 698.0540737741.

Adding to 340147433 its reverse (334741043), we get a palindrome (674888476).

The spelling of 340147433 in words is "three hundred forty million, one hundred forty-seven thousand, four hundred thirty-three".