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340210421130034 = 27134371260714207
BaseRepresentation
bin100110101011010110110100…
…1010011001110001100110010
31122121120210120012100112121001
41031112231221103032030302
5324043001420302130114
63203322302043352214
7131442251246611120
oct11526555123161462
91577523505315531
10340210421130034
119944647a507a54
12321a708582266a
13117aa922008080
1460023b505a910
15294e9c1847374
hex1356b694ce332

340210421130034 has 192 divisors, whose sum is σ = 652986607730688. Its totient is φ = 129384606718080.

The previous prime is 340210421129987. The next prime is 340210421130053. The reversal of 340210421130034 is 430031124012043.

It is a happy number.

It is a junction number, because it is equal to n+sod(n) for n = 340210421129984 and 340210421130011.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 23946668559 + ... + 23946682765.

It is an arithmetic number, because the mean of its divisors is an integer number (3400971915264).

Almost surely, 2340210421130034 is an apocalyptic number.

340210421130034 is a deficient number, since it is larger than the sum of its proper divisors (312776186600654).

340210421130034 is a wasteful number, since it uses less digits than its factorization.

340210421130034 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15021 (or 14950 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 340210421130034 its reverse (430031124012043), we get a palindrome (770241545142077).

The spelling of 340210421130034 in words is "three hundred forty trillion, two hundred ten billion, four hundred twenty-one million, one hundred thirty thousand, thirty-four".