Base | Representation |
---|---|
bin | 11111101011111011… |
… | …110101011010110011 |
3 | 10020211010110122222202 |
4 | 133223323311122303 |
5 | 1024134403232011 |
6 | 23344025053415 |
7 | 2313060411404 |
oct | 375373653263 |
9 | 106733418882 |
10 | 34023102131 |
11 | 1347a177227 |
12 | 671632726b |
13 | 3292a14bc5 |
14 | 190a8939ab |
15 | d41e1423b |
hex | 7ebef56b3 |
34023102131 has 2 divisors, whose sum is σ = 34023102132. Its totient is φ = 34023102130.
The previous prime is 34023102101. The next prime is 34023102163. The reversal of 34023102131 is 13120132043.
It is a weak prime.
It is an emirp because it is prime and its reverse (13120132043) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 34023102131 - 230 = 32949360307 is a prime.
It is a super-2 number, since 2×340231021312 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (34023102101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17011551065 + 17011551066.
It is an arithmetic number, because the mean of its divisors is an integer number (17011551066).
Almost surely, 234023102131 is an apocalyptic number.
34023102131 is a deficient number, since it is larger than the sum of its proper divisors (1).
34023102131 is an equidigital number, since it uses as much as digits as its factorization.
34023102131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 34023102131 its reverse (13120132043), we get a palindrome (47143234174).
The spelling of 34023102131 in words is "thirty-four billion, twenty-three million, one hundred two thousand, one hundred thirty-one".
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