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340302510131 is a prime number
BaseRepresentation
bin1001111001110111001…
…11000011100000110011
31012112101021012200010112
410330323213003200303
521033414420311011
6420155515451535
733405004416023
oct4747347034063
91175337180115
10340302510131
11121359993711
1255b52756bab
132612377a63c
1412683977a83
158cba9ed58b
hex4f3b9c3833

340302510131 has 2 divisors, whose sum is σ = 340302510132. Its totient is φ = 340302510130.

The previous prime is 340302510127. The next prime is 340302510157. The reversal of 340302510131 is 131015203043.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 340302510131 - 22 = 340302510127 is a prime.

It is a super-2 number, since 2×3403025101312 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 340302510097 and 340302510106.

It is not a weakly prime, because it can be changed into another prime (340302530131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170151255065 + 170151255066.

It is an arithmetic number, because the mean of its divisors is an integer number (170151255066).

Almost surely, 2340302510131 is an apocalyptic number.

340302510131 is a deficient number, since it is larger than the sum of its proper divisors (1).

340302510131 is an equidigital number, since it uses as much as digits as its factorization.

340302510131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1080, while the sum is 23.

Adding to 340302510131 its reverse (131015203043), we get a palindrome (471317713174).

The spelling of 340302510131 in words is "three hundred forty billion, three hundred two million, five hundred ten thousand, one hundred thirty-one".