Base | Representation |
---|---|
bin | 1111011110100010000100… |
… | …10111100101010101110111 |
3 | 11110111122211020122202202202 |
4 | 13233101002113211111313 |
5 | 13430110010142111043 |
6 | 200215111524255115 |
7 | 10111623003400016 |
oct | 757210227452567 |
9 | 143448736582682 |
10 | 34034434332023 |
11 | a931a169a4a64 |
12 | 399812724149b |
13 | 15cb5831c3778 |
14 | 8593bda28a7d |
15 | 3e04a8d291b8 |
hex | 1ef4425e5577 |
34034434332023 has 4 divisors (see below), whose sum is σ = 34034653205280. Its totient is φ = 34034215458768.
The previous prime is 34034434331977. The next prime is 34034434332029. The reversal of 34034434332023 is 32023343443043.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 34034434332023 - 224 = 34034417554807 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (34034434332029) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 109203215 + ... + 109514432.
It is an arithmetic number, because the mean of its divisors is an integer number (8508663301320).
Almost surely, 234034434332023 is an apocalyptic number.
34034434332023 is a deficient number, since it is larger than the sum of its proper divisors (218873257).
34034434332023 is a wasteful number, since it uses less digits than its factorization.
34034434332023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 218873256.
The product of its (nonzero) digits is 746496, while the sum is 38.
Adding to 34034434332023 its reverse (32023343443043), we get a palindrome (66057777775066).
The spelling of 34034434332023 in words is "thirty-four trillion, thirty-four billion, four hundred thirty-four million, three hundred thirty-two thousand, twenty-three".
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