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3404034000553 is a prime number
BaseRepresentation
bin110001100010010000001…
…111001100011010101001
3110001102101222112002212211
4301202100033030122221
5421232430201004203
611123442554205121
7500635064411464
oct61422017143251
913042358462784
103404034000553
1110a27084a542a
1246b8841237a1
131b8ccab35804
14baa82b402db
155d83037bc6d
hex318903cc6a9

3404034000553 has 2 divisors, whose sum is σ = 3404034000554. Its totient is φ = 3404034000552.

The previous prime is 3404034000481. The next prime is 3404034000589. The reversal of 3404034000553 is 3550004304043.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2985679879744 + 418354120809 = 1727912^2 + 646803^2 .

It is a cyclic number.

It is not a de Polignac number, because 3404034000553 - 29 = 3404034000041 is a prime.

It is not a weakly prime, because it can be changed into another prime (3404034000053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1702017000276 + 1702017000277.

It is an arithmetic number, because the mean of its divisors is an integer number (1702017000277).

Almost surely, 23404034000553 is an apocalyptic number.

It is an amenable number.

3404034000553 is a deficient number, since it is larger than the sum of its proper divisors (1).

3404034000553 is an equidigital number, since it uses as much as digits as its factorization.

3404034000553 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 43200, while the sum is 31.

Adding to 3404034000553 its reverse (3550004304043), we get a palindrome (6954038304596).

The spelling of 3404034000553 in words is "three trillion, four hundred four billion, thirty-four million, five hundred fifty-three", and thus it is an aban number.