Base | Representation |
---|---|
bin | 110001100010010000001… |
… | …111001100011010101001 |
3 | 110001102101222112002212211 |
4 | 301202100033030122221 |
5 | 421232430201004203 |
6 | 11123442554205121 |
7 | 500635064411464 |
oct | 61422017143251 |
9 | 13042358462784 |
10 | 3404034000553 |
11 | 10a27084a542a |
12 | 46b8841237a1 |
13 | 1b8ccab35804 |
14 | baa82b402db |
15 | 5d83037bc6d |
hex | 318903cc6a9 |
3404034000553 has 2 divisors, whose sum is σ = 3404034000554. Its totient is φ = 3404034000552.
The previous prime is 3404034000481. The next prime is 3404034000589. The reversal of 3404034000553 is 3550004304043.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2985679879744 + 418354120809 = 1727912^2 + 646803^2 .
It is a cyclic number.
It is not a de Polignac number, because 3404034000553 - 29 = 3404034000041 is a prime.
It is not a weakly prime, because it can be changed into another prime (3404034000053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1702017000276 + 1702017000277.
It is an arithmetic number, because the mean of its divisors is an integer number (1702017000277).
Almost surely, 23404034000553 is an apocalyptic number.
It is an amenable number.
3404034000553 is a deficient number, since it is larger than the sum of its proper divisors (1).
3404034000553 is an equidigital number, since it uses as much as digits as its factorization.
3404034000553 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 43200, while the sum is 31.
Adding to 3404034000553 its reverse (3550004304043), we get a palindrome (6954038304596).
The spelling of 3404034000553 in words is "three trillion, four hundred four billion, thirty-four million, five hundred fifty-three", and thus it is an aban number.
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