Base | Representation |
---|---|
bin | 100110101100111101101011… |
… | …1011011111100101011010001 |
3 | 1122122100220201110221202002021 |
4 | 1031121323113123330223101 |
5 | 324110111311413242114 |
6 | 3204011552534451441 |
7 | 131464231163236162 |
oct | 11531732733745321 |
9 | 1578326643852067 |
10 | 340431312243409 |
11 | 9952112180a902 |
12 | 32221a51803b81 |
13 | 117c56c550669a |
14 | 600cd6b909769 |
15 | 29555eddab024 |
hex | 1359ed76fcad1 |
340431312243409 has 2 divisors, whose sum is σ = 340431312243410. Its totient is φ = 340431312243408.
The previous prime is 340431312243397. The next prime is 340431312243427. The reversal of 340431312243409 is 904342213134043.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 337239140421184 + 3192171822225 = 18364072^2 + 1786665^2 .
It is a cyclic number.
It is not a de Polignac number, because 340431312243409 - 223 = 340431303854801 is a prime.
It is not a weakly prime, because it can be changed into another prime (340431312243479) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170215656121704 + 170215656121705.
It is an arithmetic number, because the mean of its divisors is an integer number (170215656121705).
Almost surely, 2340431312243409 is an apocalyptic number.
It is an amenable number.
340431312243409 is a deficient number, since it is larger than the sum of its proper divisors (1).
340431312243409 is an equidigital number, since it uses as much as digits as its factorization.
340431312243409 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 746496, while the sum is 43.
The spelling of 340431312243409 in words is "three hundred forty trillion, four hundred thirty-one billion, three hundred twelve million, two hundred forty-three thousand, four hundred nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •