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340431341311001 is a prime number
BaseRepresentation
bin100110101100111101101100…
…1001010110101010000011001
31122122100220210111122112022202
41031121323121022311100121
5324110111341333423001
63204011555453455545
7131464231665302303
oct11531733112652031
91578326714575282
10340431341311001
1199521137163806
1232221a5b4a15b5
13117c56cb543145
14600cd71714973
1529556016ed96b
hex1359ed92b5419

340431341311001 has 2 divisors, whose sum is σ = 340431341311002. Its totient is φ = 340431341311000.

The previous prime is 340431341310997. The next prime is 340431341311021. The reversal of 340431341311001 is 100113143134043.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 177692205855376 + 162739135455625 = 13330124^2 + 12756925^2 .

It is a cyclic number.

It is not a de Polignac number, because 340431341311001 - 22 = 340431341310997 is a prime.

It is a super-2 number, since 2×3404313413110012 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (340431341311021) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170215670655500 + 170215670655501.

It is an arithmetic number, because the mean of its divisors is an integer number (170215670655501).

Almost surely, 2340431341311001 is an apocalyptic number.

It is an amenable number.

340431341311001 is a deficient number, since it is larger than the sum of its proper divisors (1).

340431341311001 is an equidigital number, since it uses as much as digits as its factorization.

340431341311001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 340431341311001 its reverse (100113143134043), we get a palindrome (440544484445044).

The spelling of 340431341311001 in words is "three hundred forty trillion, four hundred thirty-one billion, three hundred forty-one million, three hundred eleven thousand, one".