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340450234151 = 2523713490123
BaseRepresentation
bin1001111010001000110…
…10100100111100100111
31012112202120011211101112
410331010122210330213
521034220224443101
6420222314015235
733411450146216
oct4750432447447
91175676154345
10340450234151
11121425310985
1255b9411751b
13261482605c1
141269942d07d
158cc897d6bb
hex4f446a4f27

340450234151 has 4 divisors (see below), whose sum is σ = 340463749512. Its totient is φ = 340436718792.

The previous prime is 340450234147. The next prime is 340450234183. The reversal of 340450234151 is 151432054043.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 151432054043 = 295221794967.

It is a cyclic number.

It is not a de Polignac number, because 340450234151 - 22 = 340450234147 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (340450234351) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6719825 + ... + 6770298.

It is an arithmetic number, because the mean of its divisors is an integer number (85115937378).

Almost surely, 2340450234151 is an apocalyptic number.

340450234151 is a deficient number, since it is larger than the sum of its proper divisors (13515361).

340450234151 is a wasteful number, since it uses less digits than its factorization.

340450234151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13515360.

The product of its (nonzero) digits is 28800, while the sum is 32.

Adding to 340450234151 its reverse (151432054043), we get a palindrome (491882288194).

The spelling of 340450234151 in words is "three hundred forty billion, four hundred fifty million, two hundred thirty-four thousand, one hundred fifty-one".

Divisors: 1 25237 13490123 340450234151