Base | Representation |
---|---|
bin | 11111101101100010… |
… | …100110000011100001 |
3 | 10020220000011020211211 |
4 | 133231202212003201 |
5 | 1024213302240113 |
6 | 23350430310121 |
7 | 2313535364512 |
oct | 375542460341 |
9 | 106800136754 |
10 | 34050040033 |
11 | 134933a6059 |
12 | 6723358341 |
13 | 32984871a9 |
14 | 19102a6a09 |
15 | d44485b3d |
hex | 7ed8a60e1 |
34050040033 has 2 divisors, whose sum is σ = 34050040034. Its totient is φ = 34050040032.
The previous prime is 34050040007. The next prime is 34050040043. The reversal of 34050040033 is 33004005043.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 31098617104 + 2951422929 = 176348^2 + 54327^2 .
It is a cyclic number.
It is not a de Polignac number, because 34050040033 - 25 = 34050040001 is a prime.
It is a super-3 number, since 3×340500400333 (a number of 33 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 34050039986 and 34050040013.
It is not a weakly prime, because it can be changed into another prime (34050040043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17025020016 + 17025020017.
It is an arithmetic number, because the mean of its divisors is an integer number (17025020017).
Almost surely, 234050040033 is an apocalyptic number.
It is an amenable number.
34050040033 is a deficient number, since it is larger than the sum of its proper divisors (1).
34050040033 is an equidigital number, since it uses as much as digits as its factorization.
34050040033 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2160, while the sum is 22.
Adding to 34050040033 its reverse (33004005043), we get a palindrome (67054045076).
The spelling of 34050040033 in words is "thirty-four billion, fifty million, forty thousand, thirty-three".
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