Base | Representation |
---|---|
bin | 1001111011001010110… |
… | …11001110111011100001 |
3 | 1012121012011021210201201 |
4 | 10331211123032323201 |
5 | 21041334014213431 |
6 | 420353300201201 |
7 | 33431253431104 |
oct | 4754533167341 |
9 | 1177164253651 |
10 | 341004054241 |
11 | 121689998134 |
12 | 56109699201 |
13 | 26205c0a7b6 |
14 | 1270cbd473b |
15 | 8d0c3c8461 |
hex | 4f656ceee1 |
341004054241 has 2 divisors, whose sum is σ = 341004054242. Its totient is φ = 341004054240.
The previous prime is 341004054197. The next prime is 341004054263. The reversal of 341004054241 is 142450400143.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 327384230625 + 13619823616 = 572175^2 + 116704^2 .
It is a cyclic number.
It is not a de Polignac number, because 341004054241 - 27 = 341004054113 is a prime.
It is not a weakly prime, because it can be changed into another prime (341004054841) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170502027120 + 170502027121.
It is an arithmetic number, because the mean of its divisors is an integer number (170502027121).
Almost surely, 2341004054241 is an apocalyptic number.
It is an amenable number.
341004054241 is a deficient number, since it is larger than the sum of its proper divisors (1).
341004054241 is an equidigital number, since it uses as much as digits as its factorization.
341004054241 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7680, while the sum is 28.
Adding to 341004054241 its reverse (142450400143), we get a palindrome (483454454384).
The spelling of 341004054241 in words is "three hundred forty-one billion, four million, fifty-four thousand, two hundred forty-one".
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