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341057936424913 is a prime number
BaseRepresentation
bin100110110001100001011110…
…1001001011111111111010001
31122201120211010222220100112221
41031203002331021133333101
5324200343123211044123
63205211504125421041
7131560423415011501
oct11543027511377721
91581524128810487
10341057936424913
1199742949827a94
1232303390a0a781
131183c81901b936
146031413b23a01
152966a762c525d
hex13630bd25ffd1

341057936424913 has 2 divisors, whose sum is σ = 341057936424914. Its totient is φ = 341057936424912.

The previous prime is 341057936424893. The next prime is 341057936425027. The reversal of 341057936424913 is 319424639750143.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 324911908747969 + 16146027676944 = 18025313^2 + 4018212^2 .

It is an emirp because it is prime and its reverse (319424639750143) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 341057936424913 - 237 = 340920497471441 is a prime.

It is not a weakly prime, because it can be changed into another prime (341057936424113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170528968212456 + 170528968212457.

It is an arithmetic number, because the mean of its divisors is an integer number (170528968212457).

Almost surely, 2341057936424913 is an apocalyptic number.

It is an amenable number.

341057936424913 is a deficient number, since it is larger than the sum of its proper divisors (1).

341057936424913 is an equidigital number, since it uses as much as digits as its factorization.

341057936424913 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 58786560, while the sum is 61.

The spelling of 341057936424913 in words is "three hundred forty-one trillion, fifty-seven billion, nine hundred thirty-six million, four hundred twenty-four thousand, nine hundred thirteen".