Base | Representation |
---|---|
bin | 11111110001000111… |
… | …110111101010001001 |
3 | 10021001012020210202211 |
4 | 133301013313222021 |
5 | 1024324144034423 |
6 | 23400414425121 |
7 | 2315165301244 |
oct | 376107675211 |
9 | 107035223684 |
10 | 34110143113 |
11 | 13514317422 |
12 | 673b5021a1 |
13 | 32a7a6c047 |
14 | 191827025b |
15 | d498a910d |
hex | 7f11f7a89 |
34110143113 has 2 divisors, whose sum is σ = 34110143114. Its totient is φ = 34110143112.
The previous prime is 34110143087. The next prime is 34110143141. The reversal of 34110143113 is 31134101143.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 21546423369 + 12563719744 = 146787^2 + 112088^2 .
It is an emirp because it is prime and its reverse (31134101143) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 34110143113 - 29 = 34110142601 is a prime.
It is not a weakly prime, because it can be changed into another prime (34110143173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17055071556 + 17055071557.
It is an arithmetic number, because the mean of its divisors is an integer number (17055071557).
Almost surely, 234110143113 is an apocalyptic number.
It is an amenable number.
34110143113 is a deficient number, since it is larger than the sum of its proper divisors (1).
34110143113 is an equidigital number, since it uses as much as digits as its factorization.
34110143113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 34110143113 its reverse (31134101143), we get a palindrome (65244244256).
The spelling of 34110143113 in words is "thirty-four billion, one hundred ten million, one hundred forty-three thousand, one hundred thirteen".
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