34112144121113 has 2 divisors, whose sum is σ = 34112144121114. Its totient is φ = 34112144121112.

The previous prime is 34112144121101. The next prime is 34112144121131. The reversal of 34112144121113 is 31112144121143.

Together with next prime (34112144121131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 21859252950544 + 12252891170569 = 4675388^2 + 3500413^2 .

It is an emirp because it is prime and its reverse (31112144121143) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 34112144121113 - 2¹² = 34112144117017 is a prime.

It is not a weakly prime, because it can be changed into another prime (34112144121173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17056072060556 + 17056072060557.

It is an arithmetic number, because the mean of its divisors is an integer number (17056072060557).

Almost surely, 2^{34112144121113} is an apocalyptic number.

It is an amenable number.

34112144121113 is a deficient number, since it is larger than the sum of its proper divisors (1).

34112144121113 is an equidigital number, since it uses as much as digits as its factorization.

34112144121113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2304, while the sum is 29.

Adding to 34112144121113 its reverse (31112144121143), we get a palindrome (65224288242256).

The spelling of 34112144121113 in words is "thirty-four trillion, one hundred twelve billion, one hundred forty-four million, one hundred twenty-one thousand, one hundred thirteen".