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3411313160444 = 227121832612873
BaseRepresentation
bin110001101001000010000…
…110111111000011111100
3110002010012021112202001022
4301221002012333003330
5421342332132113234
611131045144003312
7501313343302130
oct61510206770374
913063167482038
103411313160444
1110a5803389a52
12471175a60538
131b98bac20907
14bb1737a73c0
155db09439e2e
hex31a421bf0fc

3411313160444 has 12 divisors (see below), whose sum is σ = 6822626320944. Its totient is φ = 1461991354464.

The previous prime is 3411313160429. The next prime is 3411313160473. The reversal of 3411313160444 is 4440613131143.

3411313160444 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

3411313160444 is an admirable number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 60916306409 + ... + 60916306464.

It is an arithmetic number, because the mean of its divisors is an integer number (568552193412).

Almost surely, 23411313160444 is an apocalyptic number.

It is an amenable number.

3411313160444 is a primitive abundant number, since it is smaller than the sum of its proper divisors, none of which is abundant.

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

3411313160444 is a wasteful number, since it uses less digits than its factorization.

3411313160444 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 121832612884 (or 121832612882 counting only the distinct ones).

The product of its (nonzero) digits is 41472, while the sum is 35.

Adding to 3411313160444 its reverse (4440613131143), we get a palindrome (7851926291587).

The spelling of 3411313160444 in words is "three trillion, four hundred eleven billion, three hundred thirteen million, one hundred sixty thousand, four hundred forty-four".

Divisors: 1 2 4 7 14 28 121832612873 243665225746 487330451492 852828290111 1705656580222 3411313160444