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34114251001 is a prime number
BaseRepresentation
bin11111110001010111…
…100010100011111001
310021001110222111201211
4133301113202203321
51024331222013001
623401042443121
72315245230505
oct376127424371
9107043874654
1034114251001
1113516672776
1267409634a1
1332a8879a4c
141918a1d305
15d49e1b351
hex7f15e28f9

34114251001 has 2 divisors, whose sum is σ = 34114251002. Its totient is φ = 34114251000.

The previous prime is 34114250993. The next prime is 34114251047. The reversal of 34114251001 is 10015241143.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 32914667776 + 1199583225 = 181424^2 + 34635^2 .

It is an emirp because it is prime and its reverse (10015241143) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 34114251001 - 23 = 34114250993 is a prime.

It is not a weakly prime, because it can be changed into another prime (34114251091) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17057125500 + 17057125501.

It is an arithmetic number, because the mean of its divisors is an integer number (17057125501).

Almost surely, 234114251001 is an apocalyptic number.

It is an amenable number.

34114251001 is a deficient number, since it is larger than the sum of its proper divisors (1).

34114251001 is an equidigital number, since it uses as much as digits as its factorization.

34114251001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 480, while the sum is 22.

Adding to 34114251001 its reverse (10015241143), we get a palindrome (44129492144).

The spelling of 34114251001 in words is "thirty-four billion, one hundred fourteen million, two hundred fifty-one thousand, one".