Base | Representation |
---|---|
bin | 110001101001110011110… |
… | …110011111111011100011 |
3 | 110002012100102212201022112 |
4 | 301221303312133323203 |
5 | 421401034302340202 |
6 | 11131304035025535 |
7 | 501343125620315 |
oct | 61516366377343 |
9 | 13065312781275 |
10 | 3412147699427 |
11 | 10a60a1470495 |
12 | 47136943b2ab |
13 | 1b99c1aa776c |
14 | bb2125637b5 |
15 | 5db57835b52 |
hex | 31a73d9fee3 |
3412147699427 has 2 divisors, whose sum is σ = 3412147699428. Its totient is φ = 3412147699426.
The previous prime is 3412147699319. The next prime is 3412147699459. The reversal of 3412147699427 is 7249967412143.
3412147699427 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3412147699427 - 232 = 3407852732131 is a prime.
It is a super-2 number, since 2×34121476994272 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (3412147692427) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1706073849713 + 1706073849714.
It is an arithmetic number, because the mean of its divisors is an integer number (1706073849714).
Almost surely, 23412147699427 is an apocalyptic number.
3412147699427 is a deficient number, since it is larger than the sum of its proper divisors (1).
3412147699427 is an equidigital number, since it uses as much as digits as its factorization.
3412147699427 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 18289152, while the sum is 59.
The spelling of 3412147699427 in words is "three trillion, four hundred twelve billion, one hundred forty-seven million, six hundred ninety-nine thousand, four hundred twenty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.085 sec. • engine limits •