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34123306217137 is a prime number
BaseRepresentation
bin1111100001000111100111…
…00010111010111010110001
311110211011012212210022012021
413300203303202322322301
513433034012342422022
6200324010325231441
710121220224062624
oct760436342727261
9143734185708167
1034123306217137
11a9666818486a5
1239b13aa262581
131606a773a0137
1485d810b89dbb
153e295b1197c7
hex1f08f38baeb1

34123306217137 has 2 divisors, whose sum is σ = 34123306217138. Its totient is φ = 34123306217136.

The previous prime is 34123306217123. The next prime is 34123306217173. The reversal of 34123306217137 is 73171260332143.

Together with next prime (34123306217173) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 21150515862961 + 12972790354176 = 4598969^2 + 3601776^2 .

It is a cyclic number.

It is not a de Polignac number, because 34123306217137 - 219 = 34123305692849 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 34123306217093 and 34123306217102.

It is not a weakly prime, because it can be changed into another prime (34123306217107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17061653108568 + 17061653108569.

It is an arithmetic number, because the mean of its divisors is an integer number (17061653108569).

Almost surely, 234123306217137 is an apocalyptic number.

It is an amenable number.

34123306217137 is a deficient number, since it is larger than the sum of its proper divisors (1).

34123306217137 is an equidigital number, since it uses as much as digits as its factorization.

34123306217137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 381024, while the sum is 43.

The spelling of 34123306217137 in words is "thirty-four trillion, one hundred twenty-three billion, three hundred six million, two hundred seventeen thousand, one hundred thirty-seven".