341240301333044 has 48 divisors (see below), whose sum is σ = 598390982649600. Its totient is φ = 170271856567296.

The previous prime is 341240301333037. The next prime is 341240301333059. The reversal of 341240301333044 is 440333103042143.

It is a junction number, because it is equal to n+sod(n) for n = 341240301332995 and 341240301333013.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 29374213124 + ... + 29374224740.

It is an arithmetic number, because the mean of its divisors is an integer number (12466478805200).

Almost surely, 2^{341240301333044} is an apocalyptic number.

It is an amenable number.

341240301333044 is a deficient number, since it is larger than the sum of its proper divisors (257150681316556).

341240301333044 is a wasteful number, since it uses less digits than its factorization.

341240301333044 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19152 (or 19150 counting only the distinct ones).

The product of its (nonzero) digits is 124416, while the sum is 35.

Adding to 341240301333044 its reverse (440333103042143), we get a palindrome (781573404375187).

The spelling of 341240301333044 in words is "three hundred forty-one trillion, two hundred forty billion, three hundred one million, three hundred thirty-three thousand, forty-four".