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341243121342143 = 397859554461819
BaseRepresentation
bin100110110010110111101101…
…1000001111001011010111111
31122202020112010211222212010002
41031211233123001321122333
5324211411403030422033
63205432531545104515
7131610000442564406
oct11545573301713277
91582215124885102
10341243121342143
1199804438898229
1232333252a8813b
131185411bbc7b37
14603a38039863d
15296b7b3cb03e8
hex1365bdb0796bf

341243121342143 has 4 divisors (see below), whose sum is σ = 342102675804360. Its totient is φ = 340383566879928.

The previous prime is 341243121342049. The next prime is 341243121342217.

341243121342143 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-341243121342143 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 341243121342097 and 341243121342106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (341243121242143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 429777230513 + ... + 429777231306.

It is an arithmetic number, because the mean of its divisors is an integer number (85525668951090).

Almost surely, 2341243121342143 is an apocalyptic number.

341243121342143 is a deficient number, since it is larger than the sum of its proper divisors (859554462217).

341243121342143 is an equidigital number, since it uses as much as digits as its factorization.

341243121342143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 859554462216.

The product of its digits is 165888, while the sum is 38.

The spelling of 341243121342143 in words is "three hundred forty-one trillion, two hundred forty-three billion, one hundred twenty-one million, three hundred forty-two thousand, one hundred forty-three".

Divisors: 1 397 859554461819 341243121342143