3413004251581 has 4 divisors (see below), whose sum is σ = 3414838215964. Its totient is φ = 3411170287200.

The previous prime is 3413004251557. The next prime is 3413004251593. The reversal of 3413004251581 is 1851524003143.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1368118551556 + 2044885700025 = 1169666^2 + 1429995^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3413004251581 is a prime.

It is a super-2 number, since 2×3413004251581² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 3413004251581.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3413004255581) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 916979400 + ... + 916983121.

It is an arithmetic number, because the mean of its divisors is an integer number (853709553991).

Almost surely, 2^{3413004251581} is an apocalyptic number.

It is an amenable number.

3413004251581 is a deficient number, since it is larger than the sum of its proper divisors (1833964383).

3413004251581 is a wasteful number, since it uses less digits than its factorization.

3413004251581 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1833964382.

The product of its (nonzero) digits is 57600, while the sum is 37.

The spelling of 3413004251581 in words is "three trillion, four hundred thirteen billion, four million, two hundred fifty-one thousand, five hundred eighty-one".