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3413004255581 is a prime number
BaseRepresentation
bin110001101010100110111…
…010000000000101011101
3110002021120010122021110112
4301222212322000011131
5421404313042134311
611131525034015405
7501403266335504
oct61524672000535
913067503567415
103413004255581
1110a64a0a1a838
12471568277565
131b9aca39cc1b
14bb29421183b
155dba7b3028b
hex31aa6e8015d

3413004255581 has 2 divisors, whose sum is σ = 3413004255582. Its totient is φ = 3413004255580.

The previous prime is 3413004255571. The next prime is 3413004255589. The reversal of 3413004255581 is 1855524003143.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3388669815556 + 24334440025 = 1840834^2 + 155995^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3413004255581 is a prime.

It is a super-2 number, since 2×34130042555812 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3413004255589) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1706502127790 + 1706502127791.

It is an arithmetic number, because the mean of its divisors is an integer number (1706502127791).

Almost surely, 23413004255581 is an apocalyptic number.

It is an amenable number.

3413004255581 is a deficient number, since it is larger than the sum of its proper divisors (1).

3413004255581 is an equidigital number, since it uses as much as digits as its factorization.

3413004255581 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 288000, while the sum is 41.

The spelling of 3413004255581 in words is "three trillion, four hundred thirteen billion, four million, two hundred fifty-five thousand, five hundred eighty-one".