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34130613160537 is a prime number
BaseRepresentation
bin1111100001010101001110…
…00100101100101001011001
311110211212002010002111011121
413300222213010230221121
513433143443432114122
6200331215350325241
710121566261060615
oct760524704545131
9143755063074147
1034130613160537
11a9697913893a3
1239b28a9359821
13160767016539a
1485dd053a6345
153e2c37864bc7
hex1f0aa712ca59

34130613160537 has 2 divisors, whose sum is σ = 34130613160538. Its totient is φ = 34130613160536.

The previous prime is 34130613160493. The next prime is 34130613160571. The reversal of 34130613160537 is 73506131603143.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 32571001824201 + 1559611336336 = 5707101^2 + 1248844^2 .

It is a cyclic number.

It is not a de Polignac number, because 34130613160537 - 219 = 34130612636249 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 34130613160493 and 34130613160502.

It is not a weakly prime, because it can be changed into another prime (34130613160937) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17065306580268 + 17065306580269.

It is an arithmetic number, because the mean of its divisors is an integer number (17065306580269).

Almost surely, 234130613160537 is an apocalyptic number.

It is an amenable number.

34130613160537 is a deficient number, since it is larger than the sum of its proper divisors (1).

34130613160537 is an equidigital number, since it uses as much as digits as its factorization.

34130613160537 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 408240, while the sum is 43.

The spelling of 34130613160537 in words is "thirty-four trillion, one hundred thirty billion, six hundred thirteen million, one hundred sixty thousand, five hundred thirty-seven".