Base | Representation |
---|---|
bin | 110001101010101010010… |
… | …101010100001011011011 |
3 | 110002021201010211011102212 |
4 | 301222222111110023123 |
5 | 421404422301404134 |
6 | 11131534450145335 |
7 | 501404565115262 |
oct | 61525225241333 |
9 | 13067633734385 |
10 | 3413061747419 |
11 | 10a6520418255 |
12 | 47158358224b |
13 | 1b9b0927c36c |
14 | bb29bad95d9 |
15 | 5dbacbd9bce |
hex | 31aaa5542db |
3413061747419 has 2 divisors, whose sum is σ = 3413061747420. Its totient is φ = 3413061747418.
The previous prime is 3413061747413. The next prime is 3413061747451. The reversal of 3413061747419 is 9147471603143.
3413061747419 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3413061747419 - 236 = 3344342270683 is a prime.
It is a super-2 number, since 2×34130617474192 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (3413061747413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1706530873709 + 1706530873710.
It is an arithmetic number, because the mean of its divisors is an integer number (1706530873710).
Almost surely, 23413061747419 is an apocalyptic number.
3413061747419 is a deficient number, since it is larger than the sum of its proper divisors (1).
3413061747419 is an equidigital number, since it uses as much as digits as its factorization.
3413061747419 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1524096, while the sum is 50.
The spelling of 3413061747419 in words is "three trillion, four hundred thirteen billion, sixty-one million, seven hundred forty-seven thousand, four hundred nineteen".
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