Base | Representation |
---|---|
bin | 110001101010101110000… |
… | …011100110100110010111 |
3 | 110002021212111100202022012 |
4 | 301222232003212212113 |
5 | 421410034244310033 |
6 | 11131545001054435 |
7 | 501406254062141 |
oct | 61525603464627 |
9 | 13067774322265 |
10 | 3413124213143 |
11 | 10a6552702717 |
12 | 4715a048741b |
13 | 1b9b191b0728 |
14 | bb2a6119c91 |
15 | 5dbb3428248 |
hex | 31aae0e6997 |
3413124213143 has 6 divisors (see below), whose sum is σ = 3494345126544. Its totient is φ = 3333749229636.
The previous prime is 3413124213119. The next prime is 3413124213151.
3413124213143 is nontrivially palindromic in base 10.
3413124213143 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 3413124213143 - 216 = 3413124147607 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3413124213173) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 922963055 + ... + 922966752.
It is an arithmetic number, because the mean of its divisors is an integer number (582390854424).
Almost surely, 23413124213143 is an apocalyptic number.
3413124213143 is a deficient number, since it is larger than the sum of its proper divisors (81220913401).
3413124213143 is an equidigital number, since it uses as much as digits as its factorization.
3413124213143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1845929893 (or 1845929850 counting only the distinct ones).
The product of its digits is 20736, while the sum is 32.
The spelling of 3413124213143 in words is "three trillion, four hundred thirteen billion, one hundred twenty-four million, two hundred thirteen thousand, one hundred forty-three".
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