Base | Representation |
---|---|
bin | 110001101010110110101… |
… | …110111110100001011111 |
3 | 110002022020122022101101002 |
4 | 301222312232332201133 |
5 | 421410334032113210 |
6 | 11132011241340515 |
7 | 501413002414532 |
oct | 61526656764137 |
9 | 13068218271332 |
10 | 3413269801055 |
11 | 10a6617901004 |
12 | 47162119773b |
13 | 1b9b403c631a |
14 | bb2bb5b6a19 |
15 | 5dbc10d54a5 |
hex | 31ab6bbe85f |
3413269801055 has 4 divisors (see below), whose sum is σ = 4095923761272. Its totient is φ = 2730615840840.
The previous prime is 3413269801049. The next prime is 3413269801087. The reversal of 3413269801055 is 5501089623143.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 3413269801055 - 218 = 3413269538911 is a prime.
It is a super-2 number, since 2×34132698010552 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 341326980101 + ... + 341326980110.
It is an arithmetic number, because the mean of its divisors is an integer number (1023980940318).
Almost surely, 23413269801055 is an apocalyptic number.
3413269801055 is a deficient number, since it is larger than the sum of its proper divisors (682653960217).
3413269801055 is an equidigital number, since it uses as much as digits as its factorization.
3413269801055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 682653960216.
The product of its (nonzero) digits is 777600, while the sum is 47.
The spelling of 3413269801055 in words is "three trillion, four hundred thirteen billion, two hundred sixty-nine million, eight hundred one thousand, fifty-five".
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