Search a number
-
+
341332452030041 is a prime number
BaseRepresentation
bin100110110011100001010011…
…1100011011011011001011001
31122202120001201110102222122022
41031213002213203123121121
5324214342330204430131
63205541544055504225
7131616312234111623
oct11547024743333131
91582501643388568
10341332452030041
119983930971a21a
1232348623688075
131185c687163b44
146040816429c13
15296dc914cc37b
hex13670a78db659

341332452030041 has 2 divisors, whose sum is σ = 341332452030042. Its totient is φ = 341332452030040.

The previous prime is 341332452029999. The next prime is 341332452030067. The reversal of 341332452030041 is 140030254233143.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 340501399182400 + 831052847641 = 18452680^2 + 911621^2 .

It is an emirp because it is prime and its reverse (140030254233143) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 341332452030041 - 222 = 341332447835737 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 341332452029983 and 341332452030010.

It is not a weakly prime, because it can be changed into another prime (341332452930041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170666226015020 + 170666226015021.

It is an arithmetic number, because the mean of its divisors is an integer number (170666226015021).

Almost surely, 2341332452030041 is an apocalyptic number.

It is an amenable number.

341332452030041 is a deficient number, since it is larger than the sum of its proper divisors (1).

341332452030041 is an equidigital number, since it uses as much as digits as its factorization.

341332452030041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 103680, while the sum is 35.

The spelling of 341332452030041 in words is "three hundred forty-one trillion, three hundred thirty-two billion, four hundred fifty-two million, thirty thousand, forty-one".