Base | Representation |
---|---|
bin | 110001101011000001100… |
… | …010100111011100111011 |
3 | 110002022201021110211202201 |
4 | 301223001202213130323 |
5 | 421411221441011303 |
6 | 11132041235411031 |
7 | 501420333464611 |
oct | 61530142473473 |
9 | 13068637424681 |
10 | 3413451110203 |
11 | 10a6700188282 |
12 | 471671a53a77 |
13 | 1b9b6bb38044 |
14 | bb2d76d16b1 |
15 | 5dbd1e9b81d |
hex | 31ac18a773b |
3413451110203 has 2 divisors, whose sum is σ = 3413451110204. Its totient is φ = 3413451110202.
The previous prime is 3413451110197. The next prime is 3413451110227. The reversal of 3413451110203 is 3020111543143.
3413451110203 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3413451110203 - 213 = 3413451102011 is a prime.
It is not a weakly prime, because it can be changed into another prime (3413451110233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1706725555101 + 1706725555102.
It is an arithmetic number, because the mean of its divisors is an integer number (1706725555102).
Almost surely, 23413451110203 is an apocalyptic number.
3413451110203 is a deficient number, since it is larger than the sum of its proper divisors (1).
3413451110203 is an equidigital number, since it uses as much as digits as its factorization.
3413451110203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 3413451110203 its reverse (3020111543143), we get a palindrome (6433562653346).
The spelling of 3413451110203 in words is "three trillion, four hundred thirteen billion, four hundred fifty-one million, one hundred ten thousand, two hundred three".
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