341401140012003 has 4 divisors (see below), whose sum is σ = 455201520016008. Its totient is φ = 227600760008000.

The previous prime is 341401140011989. The next prime is 341401140012013. The reversal of 341401140012003 is 300210041104143.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 341401140012003 - 2²⁵ = 341401106457571 is a prime.

It is not an unprimeable number, because it can be changed into a prime (341401140012013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 56900190001998 + ... + 56900190002003.

It is an arithmetic number, because the mean of its divisors is an integer number (113800380004002).

Almost surely, 2^{341401140012003} is an apocalyptic number.

341401140012003 is a deficient number, since it is larger than the sum of its proper divisors (113800380004005).

341401140012003 is a wasteful number, since it uses less digits than its factorization.

341401140012003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 113800380004004.

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 341401140012003 its reverse (300210041104143), we get a palindrome (641611181116146).

The spelling of 341401140012003 in words is "three hundred forty-one trillion, four hundred one billion, one hundred forty million, twelve thousand, three".