341401140012013 has 2 divisors, whose sum is σ = 341401140012014. Its totient is φ = 341401140012012.

The previous prime is 341401140011989. The next prime is 341401140012061. The reversal of 341401140012013 is 310210041104143.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 338674936153129 + 2726203858884 = 18403123^2 + 1651122^2 .

It is an emirp because it is prime and its reverse (310210041104143) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-341401140012013 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (341401140052013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170700570006006 + 170700570006007.

It is an arithmetic number, because the mean of its divisors is an integer number (170700570006007).

Almost surely, 2^{341401140012013} is an apocalyptic number.

It is an amenable number.

341401140012013 is a deficient number, since it is larger than the sum of its proper divisors (1).

341401140012013 is an equidigital number, since it uses as much as digits as its factorization.

341401140012013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 341401140012013 its reverse (310210041104143), we get a palindrome (651611181116156).

The spelling of 341401140012013 in words is "three hundred forty-one trillion, four hundred one billion, one hundred forty million, twelve thousand, thirteen".