Base | Representation |
---|---|
bin | 110001101011110000101… |
… | …011110000001010010011 |
3 | 110002101202101201221200122 |
4 | 301223300223300022103 |
5 | 421414331430044243 |
6 | 11132251531540455 |
7 | 501446046311051 |
oct | 61536053601223 |
9 | 13071671657618 |
10 | 3414242034323 |
11 | 10a6a7668a27a |
12 | 4718528ba72b |
13 | 1b9c66960b93 |
14 | bb3707771d1 |
15 | 5dc2b62e668 |
hex | 31af0af0293 |
3414242034323 has 2 divisors, whose sum is σ = 3414242034324. Its totient is φ = 3414242034322.
The previous prime is 3414242034197. The next prime is 3414242034331. The reversal of 3414242034323 is 3234302424143.
3414242034323 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3414242034323 - 214 = 3414242017939 is a prime.
It is not a weakly prime, because it can be changed into another prime (3414242004323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1707121017161 + 1707121017162.
It is an arithmetic number, because the mean of its divisors is an integer number (1707121017162).
Almost surely, 23414242034323 is an apocalyptic number.
3414242034323 is a deficient number, since it is larger than the sum of its proper divisors (1).
3414242034323 is an equidigital number, since it uses as much as digits as its factorization.
3414242034323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 165888, while the sum is 35.
Adding to 3414242034323 its reverse (3234302424143), we get a palindrome (6648544458466).
The spelling of 3414242034323 in words is "three trillion, four hundred fourteen billion, two hundred forty-two million, thirty-four thousand, three hundred twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •