Base | Representation |
---|---|
bin | 1111100001101110101111… |
… | …01010001001011101100011 |
3 | 11110220011102220002220020112 |
4 | 13300313113222021131203 |
5 | 13433410023133424042 |
6 | 200341403025401535 |
7 | 10122562624264343 |
oct | 760672752113543 |
9 | 143804386086215 |
10 | 34144313186147 |
11 | a97458172040a |
12 | 39b54914992ab |
13 | 1608a44585008 |
14 | 860844ab4d23 |
15 | 3e328a491982 |
hex | 1f0dd7a89763 |
34144313186147 has 2 divisors, whose sum is σ = 34144313186148. Its totient is φ = 34144313186146.
The previous prime is 34144313186117. The next prime is 34144313186209. The reversal of 34144313186147 is 74168131344143.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 34144313186147 - 218 = 34144312924003 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 34144313186095 and 34144313186104.
It is not a weakly prime, because it can be changed into another prime (34144313186107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17072156593073 + 17072156593074.
It is an arithmetic number, because the mean of its divisors is an integer number (17072156593074).
Almost surely, 234144313186147 is an apocalyptic number.
34144313186147 is a deficient number, since it is larger than the sum of its proper divisors (1).
34144313186147 is an equidigital number, since it uses as much as digits as its factorization.
34144313186147 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2322432, while the sum is 50.
The spelling of 34144313186147 in words is "thirty-four trillion, one hundred forty-four billion, three hundred thirteen million, one hundred eighty-six thousand, one hundred forty-seven".
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