Base | Representation |
---|---|
bin | 11111110011001110… |
… | …000110111110010001 |
3 | 10021010122110122102001 |
4 | 133303032012332101 |
5 | 1024412201130022 |
6 | 23404112554001 |
7 | 2316103354126 |
oct | 376316067621 |
9 | 107118418361 |
10 | 34145333137 |
11 | 13532172193 |
12 | 674b252901 |
13 | 32b2140446 |
14 | 191cbd074d |
15 | d4ca0ab27 |
hex | 7f3386f91 |
34145333137 has 2 divisors, whose sum is σ = 34145333138. Its totient is φ = 34145333136.
The previous prime is 34145333111. The next prime is 34145333147. The reversal of 34145333137 is 73133354143.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 19004276736 + 15141056401 = 137856^2 + 123049^2 .
It is a cyclic number.
It is not a de Polignac number, because 34145333137 - 211 = 34145331089 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 34145333096 and 34145333105.
It is not a weakly prime, because it can be changed into another prime (34145333107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17072666568 + 17072666569.
It is an arithmetic number, because the mean of its divisors is an integer number (17072666569).
Almost surely, 234145333137 is an apocalyptic number.
It is an amenable number.
34145333137 is a deficient number, since it is larger than the sum of its proper divisors (1).
34145333137 is an equidigital number, since it uses as much as digits as its factorization.
34145333137 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 136080, while the sum is 37.
The spelling of 34145333137 in words is "thirty-four billion, one hundred forty-five million, three hundred thirty-three thousand, one hundred thirty-seven".
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