Base | Representation |
---|---|
bin | 11111110011101011… |
… | …011001010111010001 |
3 | 10021011011220200222001 |
4 | 133303223121113101 |
5 | 1024421132320031 |
6 | 23404545314001 |
7 | 2316225541411 |
oct | 376353312721 |
9 | 107134820861 |
10 | 34153010641 |
11 | 13536536432 |
12 | 6751935901 |
13 | 32b38cab49 |
14 | 191dc2c641 |
15 | d4d525861 |
hex | 7f3ad95d1 |
34153010641 has 2 divisors, whose sum is σ = 34153010642. Its totient is φ = 34153010640.
The previous prime is 34153010497. The next prime is 34153010711. The reversal of 34153010641 is 14601035143.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 28537007041 + 5616003600 = 168929^2 + 74940^2 .
It is an emirp because it is prime and its reverse (14601035143) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 34153010641 - 217 = 34152879569 is a prime.
It is not a weakly prime, because it can be changed into another prime (34153020641) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17076505320 + 17076505321.
It is an arithmetic number, because the mean of its divisors is an integer number (17076505321).
Almost surely, 234153010641 is an apocalyptic number.
It is an amenable number.
34153010641 is a deficient number, since it is larger than the sum of its proper divisors (1).
34153010641 is an equidigital number, since it uses as much as digits as its factorization.
34153010641 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 34153010641 its reverse (14601035143), we get a palindrome (48754045784).
The spelling of 34153010641 in words is "thirty-four billion, one hundred fifty-three million, ten thousand, six hundred forty-one".
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