Base | Representation |
---|---|
bin | 1001111100001101101… |
… | …11010001110001011011 |
3 | 1012122122020220112210011 |
4 | 10332012313101301123 |
5 | 21044011123212133 |
6 | 420525100302351 |
7 | 33451205025043 |
oct | 4760667216133 |
9 | 1178566815704 |
10 | 341565054043 |
11 | 121947628634 |
12 | 562455419b7 |
13 | 262951cc945 |
14 | 12763508723 |
15 | 8d417906cd |
hex | 4f86dd1c5b |
341565054043 has 2 divisors, whose sum is σ = 341565054044. Its totient is φ = 341565054042.
The previous prime is 341565054013. The next prime is 341565054067. The reversal of 341565054043 is 340450565143.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-341565054043 is a prime.
It is a super-4 number, since 4×3415650540434 (a number of 47 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 341565053987 and 341565054005.
It is not a weakly prime, because it can be changed into another prime (341565054013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170782527021 + 170782527022.
It is an arithmetic number, because the mean of its divisors is an integer number (170782527022).
Almost surely, 2341565054043 is an apocalyptic number.
341565054043 is a deficient number, since it is larger than the sum of its proper divisors (1).
341565054043 is an equidigital number, since it uses as much as digits as its factorization.
341565054043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432000, while the sum is 40.
The spelling of 341565054043 in words is "three hundred forty-one billion, five hundred sixty-five million, fifty-four thousand, forty-three".
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