341604406143 has 144 divisors (see below), whose sum is σ = 672764451840. Its totient is φ = 162178848000.

The previous prime is 341604406133. The next prime is 341604406177.

341604406143 is a `hidden beast` number, since 3 + 4 + 1 + 604 + 4 + 0 + 6 + 1 + 43 = 666.

341604406143 is nontrivially palindromic in base 10.

It is not a de Polignac number, because 341604406143 - 2⁹ = 341604405631 is a prime.

It is a super-3 number, since 3×341604406143³ (a number of 36 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 341604406098 and 341604406107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (341604406133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 11814378 + ... + 11843256.

It is an arithmetic number, because the mean of its divisors is an integer number (4671975360).

Almost surely, 2^341604406143 is an apocalyptic number.

341604406143 is a gapful number since it is divisible by the number (33) formed by its first and last digit.

341604406143 is a deficient number, since it is larger than the sum of its proper divisors (331160045697).

341604406143 is a wasteful number, since it uses less digits than its factorization.

341604406143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 29030 (or 29014 counting only the distinct ones).

The product of its (nonzero) digits is 82944, while the sum is 36.

It can be divided in two parts, 341604 and 406143, that added together give a palindrome (747747).

The spelling of 341604406143 in words is "three hundred forty-one billion, six hundred four million, four hundred six thousand, one hundred forty-three".