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3416132713481 is a prime number
BaseRepresentation
bin110001101101100001011…
…000000111110000001001
3110002120122011101101220122
4301231201120013300021
5421432214433312411
611133203311433025
7501543644650145
oct61554130076011
913076564341818
103416132713481
1110a7856949534
1247209bb25775
131ba1a8580047
14bb4ad8d6225
155dcdc5ea9db
hex31b61607c09

3416132713481 has 2 divisors, whose sum is σ = 3416132713482. Its totient is φ = 3416132713480.

The previous prime is 3416132713453. The next prime is 3416132713489. The reversal of 3416132713481 is 1843172316143.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3381019950025 + 35112763456 = 1838755^2 + 187384^2 .

It is an emirp because it is prime and its reverse (1843172316143) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3416132713481 - 210 = 3416132712457 is a prime.

It is a super-2 number, since 2×34161327134812 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (3416132713489) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1708066356740 + 1708066356741.

It is an arithmetic number, because the mean of its divisors is an integer number (1708066356741).

Almost surely, 23416132713481 is an apocalyptic number.

It is an amenable number.

3416132713481 is a deficient number, since it is larger than the sum of its proper divisors (1).

3416132713481 is an equidigital number, since it uses as much as digits as its factorization.

3416132713481 is an evil number, because the sum of its binary digits is even.

The product of its digits is 290304, while the sum is 44.

The spelling of 3416132713481 in words is "three trillion, four hundred sixteen billion, one hundred thirty-two million, seven hundred thirteen thousand, four hundred eighty-one".