Base | Representation |
---|---|
bin | 110001101101100110010… |
… | …000101011110101011011 |
3 | 110002120211212120012222001 |
4 | 301231212100223311123 |
5 | 421432401422301303 |
6 | 11133215355541431 |
7 | 501545661260545 |
oct | 61554620536533 |
9 | 13076755505861 |
10 | 3416214650203 |
11 | 10a7899122833 |
12 | 47210345a877 |
13 | 1ba1bc53ab04 |
14 | bb4ba744695 |
15 | 5dce48d331d |
hex | 31b6642bd5b |
3416214650203 has 2 divisors, whose sum is σ = 3416214650204. Its totient is φ = 3416214650202.
The previous prime is 3416214650113. The next prime is 3416214650237. The reversal of 3416214650203 is 3020564126143.
It is a strong prime.
It is an emirp because it is prime and its reverse (3020564126143) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3416214650203 - 213 = 3416214642011 is a prime.
It is not a weakly prime, because it can be changed into another prime (3416214650243) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1708107325101 + 1708107325102.
It is an arithmetic number, because the mean of its divisors is an integer number (1708107325102).
Almost surely, 23416214650203 is an apocalyptic number.
3416214650203 is a deficient number, since it is larger than the sum of its proper divisors (1).
3416214650203 is an equidigital number, since it uses as much as digits as its factorization.
3416214650203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 103680, while the sum is 37.
Adding to 3416214650203 its reverse (3020564126143), we get a palindrome (6436778776346).
The spelling of 3416214650203 in words is "three trillion, four hundred sixteen billion, two hundred fourteen million, six hundred fifty thousand, two hundred three".
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