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3420014434 = 21710007217
BaseRepresentation
bin1100101111011001…
…0100011101100010
322211100100201211021
43023312110131202
524001010430214
61323210440054
7150515433364
oct31366243542
98740321737
103420014434
1114a5566511
127b543302a
134267129a5
142462dad34
151503ac924
hexcbd94762

3420014434 has 4 divisors (see below), whose sum is σ = 5130021654. Its totient is φ = 1710007216.

The previous prime is 3420014431. The next prime is 3420014443. The reversal of 3420014434 is 4344100243.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 3404372409 + 15642025 = 58347^2 + 3955^2 .

It is a junction number, because it is equal to n+sod(n) for n = 3420014399 and 3420014408.

It is not an unprimeable number, because it can be changed into a prime (3420014431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 855003607 + ... + 855003610.

Almost surely, 23420014434 is an apocalyptic number.

3420014434 is a deficient number, since it is larger than the sum of its proper divisors (1710007220).

3420014434 is a wasteful number, since it uses less digits than its factorization.

3420014434 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1710007219.

The product of its (nonzero) digits is 4608, while the sum is 25.

The square root of 3420014434 is about 58480.8894768197. The cubic root of 3420014434 is about 1506.6393741521.

Adding to 3420014434 its reverse (4344100243), we get a palindrome (7764114677).

The spelling of 3420014434 in words is "three billion, four hundred twenty million, fourteen thousand, four hundred thirty-four".

Divisors: 1 2 1710007217 3420014434