Base | Representation |
---|---|
bin | 110001110001001110100… |
… | …101001000101111101011 |
3 | 110002221220111201122110111 |
4 | 301301032211020233223 |
5 | 422013342223404421 |
6 | 11135102232355151 |
7 | 502044400050652 |
oct | 61611645105753 |
9 | 13087814648414 |
10 | 3420112325611 |
11 | 10a9509277a83 |
12 | 472a10845ab7 |
13 | 1ba690bb3917 |
14 | bb76a260199 |
15 | 5de71b94ee1 |
hex | 31c4e948beb |
3420112325611 has 2 divisors, whose sum is σ = 3420112325612. Its totient is φ = 3420112325610.
The previous prime is 3420112325569. The next prime is 3420112325629. The reversal of 3420112325611 is 1165232110243.
It is a strong prime.
It is an emirp because it is prime and its reverse (1165232110243) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3420112325611 - 229 = 3419575454699 is a prime.
It is not a weakly prime, because it can be changed into another prime (3420112325681) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1710056162805 + 1710056162806.
It is an arithmetic number, because the mean of its divisors is an integer number (1710056162806).
Almost surely, 23420112325611 is an apocalyptic number.
3420112325611 is a deficient number, since it is larger than the sum of its proper divisors (1).
3420112325611 is an equidigital number, since it uses as much as digits as its factorization.
3420112325611 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8640, while the sum is 31.
Adding to 3420112325611 its reverse (1165232110243), we get a palindrome (4585344435854).
The spelling of 3420112325611 in words is "three trillion, four hundred twenty billion, one hundred twelve million, three hundred twenty-five thousand, six hundred eleven".
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