342012113 has 2 divisors, whose sum is σ = 342012114. Its totient is φ = 342012112.

The previous prime is 342012101. The next prime is 342012173. The reversal of 342012113 is 311210243.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 341251729 + 760384 = 18473^2 + 872^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-342012113 is a prime.

It is a Sophie Germain prime.

It is a Chen prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 342012091 and 342012100.

It is not a weakly prime, because it can be changed into another prime (342012173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 171006056 + 171006057.

It is an arithmetic number, because the mean of its divisors is an integer number (171006057).

Almost surely, 2^342012113 is an apocalyptic number.

It is an amenable number.

342012113 is a deficient number, since it is larger than the sum of its proper divisors (1).

342012113 is an equidigital number, since it uses as much as digits as its factorization.

342012113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 342012113 is about 18493.5695040195. The cubic root of 342012113 is about 699.3273218115.

Adding to 342012113 its reverse (311210243), we get a palindrome (653222356).

The spelling of 342012113 in words is "three hundred forty-two million, twelve thousand, one hundred thirteen".