34201241 has 2 divisors, whose sum is σ = 34201242. Its totient is φ = 34201240.

The previous prime is 34201231. The next prime is 34201247. The reversal of 34201241 is 14210243.

34201241 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 27931225 + 6270016 = 5285^2 + 2504^2 .

It is an emirp because it is prime and its reverse (14210243) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 34201241 - 2⁶ = 34201177 is a prime.

It is a Chen prime.

It is equal to p_2100860 and since 34201241 and 2100860 have the same sum of digits, it is a Honaker prime.

It is not a weakly prime, because it can be changed into another prime (34201247) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17100620 + 17100621.

It is an arithmetic number, because the mean of its divisors is an integer number (17100621).

Almost surely, 2^34201241 is an apocalyptic number.

It is an amenable number.

34201241 is a deficient number, since it is larger than the sum of its proper divisors (1).

34201241 is an equidigital number, since it uses as much as digits as its factorization.

34201241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 192, while the sum is 17.

The square root of 34201241 is about 5848.1827091841. The cubic root of 34201241 is about 324.5990827556.

Adding to 34201241 its reverse (14210243), we get a palindrome (48411484).

The spelling of 34201241 in words is "thirty-four million, two hundred one thousand, two hundred forty-one".