3420130125641 has 4 divisors (see below), whose sum is σ = 3429818879892. Its totient is φ = 3410441371392.

The previous prime is 3420130125637. The next prime is 3420130125673. The reversal of 3420130125641 is 1465210310243.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2451795404041 + 968334721600 = 1565821^2 + 984040^2 .

It is a cyclic number.

It is not a de Polignac number, because 3420130125641 - 2² = 3420130125637 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3420130125598 and 3420130125607.

It is not an unprimeable number, because it can be changed into a prime (3420130121641) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4844376596 + ... + 4844377301.

It is an arithmetic number, because the mean of its divisors is an integer number (857454719973).

Almost surely, 2^{3420130125641} is an apocalyptic number.

It is an amenable number.

3420130125641 is a deficient number, since it is larger than the sum of its proper divisors (9688754251).

3420130125641 is an equidigital number, since it uses as much as digits as its factorization.

3420130125641 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9688754250.

The product of its (nonzero) digits is 17280, while the sum is 32.

Adding to 3420130125641 its reverse (1465210310243), we get a palindrome (4885340435884).

The spelling of 3420130125641 in words is "three trillion, four hundred twenty billion, one hundred thirty million, one hundred twenty-five thousand, six hundred forty-one".