3420140123 has 2 divisors, whose sum is σ = 3420140124. Its totient is φ = 3420140122.

The previous prime is 3420140111. The next prime is 3420140147. The reversal of 3420140123 is 3210410243.

It is a weak prime.

It is an emirp because it is prime and its reverse (3210410243) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3420140123 - 2⁴ = 3420140107 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 3420140095 and 3420140104.

It is not a weakly prime, because it can be changed into another prime (3420140023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1710070061 + 1710070062.

It is an arithmetic number, because the mean of its divisors is an integer number (1710070062).

Almost surely, 2^3420140123 is an apocalyptic number.

3420140123 is a deficient number, since it is larger than the sum of its proper divisors (1).

3420140123 is an equidigital number, since it uses as much as digits as its factorization.

3420140123 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 20.

The square root of 3420140123 is about 58481.9640829547. The cubic root of 3420140123 is about 1506.6578307678.

Adding to 3420140123 its reverse (3210410243), we get a palindrome (6630550366).

The spelling of 3420140123 in words is "three billion, four hundred twenty million, one hundred forty thousand, one hundred twenty-three".