Base | Representation |
---|---|
bin | 110001110001011001111… |
… | …001001110011101111111 |
3 | 110002222101201220021122121 |
4 | 301301121321032131333 |
5 | 422014234322010221 |
6 | 11135133133023411 |
7 | 502052163340336 |
oct | 61613171163577 |
9 | 13088351807577 |
10 | 3420302141311 |
11 | 10a95a6434360 |
12 | 472a64324b67 |
13 | 1ba6c13134c3 |
14 | bb787550d1d |
15 | 5de8368ba41 |
hex | 31c59e4e77f |
3420302141311 has 16 divisors (see below), whose sum is σ = 3766273365888. Its totient is φ = 3080172549600.
The previous prime is 3420302141303. The next prime is 3420302141341. The reversal of 3420302141311 is 1131412030243.
It is a cyclic number.
It is not a de Polignac number, because 3420302141311 - 23 = 3420302141303 is a prime.
It is a super-2 number, since 2×34203021413112 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3420302141341) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 35736541 + ... + 35832121.
It is an arithmetic number, because the mean of its divisors is an integer number (235392085368).
Almost surely, 23420302141311 is an apocalyptic number.
3420302141311 is a deficient number, since it is larger than the sum of its proper divisors (345971224577).
3420302141311 is a wasteful number, since it uses less digits than its factorization.
3420302141311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 126102.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 3420302141311 its reverse (1131412030243), we get a palindrome (4551714171554).
The spelling of 3420302141311 in words is "three trillion, four hundred twenty billion, three hundred two million, one hundred forty-one thousand, three hundred eleven".
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