Base | Representation |
---|---|
bin | 1001111101000101100… |
… | …00110001010001100001 |
3 | 1012200211212122021000011 |
4 | 10332202300301101201 |
5 | 21100440434010423 |
6 | 421043340324521 |
7 | 33465620316022 |
oct | 4764260612141 |
9 | 1180755567004 |
10 | 342033110113 |
11 | 122067857032 |
12 | 56356243741 |
13 | 2633b17bcb6 |
14 | 127a9746c49 |
15 | 8d6c8e8b0d |
hex | 4fa2c31461 |
342033110113 has 2 divisors, whose sum is σ = 342033110114. Its totient is φ = 342033110112.
The previous prime is 342033110077. The next prime is 342033110197. The reversal of 342033110113 is 311011330243.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 179388672849 + 162644437264 = 423543^2 + 403292^2 .
It is a cyclic number.
It is not a de Polignac number, because 342033110113 - 233 = 333443175521 is a prime.
It is not a weakly prime, because it can be changed into another prime (342033110213) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 171016555056 + 171016555057.
It is an arithmetic number, because the mean of its divisors is an integer number (171016555057).
Almost surely, 2342033110113 is an apocalyptic number.
It is an amenable number.
342033110113 is a deficient number, since it is larger than the sum of its proper divisors (1).
342033110113 is an equidigital number, since it uses as much as digits as its factorization.
342033110113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 342033110113 its reverse (311011330243), we get a palindrome (653044440356).
The spelling of 342033110113 in words is "three hundred forty-two billion, thirty-three million, one hundred ten thousand, one hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •